急问-很麻烦的水平拋射

一颗球从4.9m的高度以2m/s的初速进行水平拋射
落地时会反弹不为弹性碰撞每次反弹损失当时1/5的动能
且反弹时合地面的角度皆相同问球最多可弹跳至多远?
请高手帮帮忙,谢谢

评论(1)

(1)Because:E=1/2*mV^2andthesamebounceangle
    Sothenewvelocitybecomesto2/sqrt(5)oftheoldvelocityaftereverybouncing.
(2)assumetheinitialvelocityinydirectionisVoyandtheoneinxdirectionisVox
    fromtheaboveresult,V1y=(2/sqrt(5))*Voy;V1x=(2/sqrt(5))*Vox
    (whereV1ymeansthevelocityafterthefirstbouncing)
    Similiarly,Vny=(r^n)*Voy;Vnx=(r^n)*Vox  [wherer=(2/sqrt(5))]

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